Stats 101, pinside staff take notice:
Median versus Mean
The mean is commonly known as the average = sum / number_of_items
The median is the mid-point of an ordered list of items. If the number of items is even take the average of the 2 middle ones.
Example:
The ratings for Some machine are: 7.8, 8.5, 6.9, 9.2, 9.0, 8.7, 7.0, 8.8, 7.9
average = 73.8 / 9 = 8.2
median = 8.5 (if you order the above list of 9 items 8.5 is the middle)
Now Joe Hater votes the game as 1.5
average = 7.53
median = (7.9 + 8.5) / 2 = 8.2
Instead of Joe Hater we have Joe Enthusiast vote a 10
average = 8.38
median = (8.5 + 8.7) / 2 = 8.6
The median is not nearly as susceptible to enthusiasts and haters as the average and therefore gives a more realistic rating. Outliers have a much higher tendency to affect the average but not the median.
Another example would be income. Bill Gates that makes 1 billion a year plus 1000 homeless that make nothing (= 0). On average they make about 1 million a year each, while the median being at 0 reflects more accurately the true nature of the situation.
If you have many items in your list, like 100+ votes, they tend to be very close together. In this case outliers on either end would hardly move the median when compared to the average. In the income example add Warren Buffet with another 1 billion in income. Now the average moves up to almost 2 million per year while the median is still at 0.
I think the income example best illustrates the flaws of taking the average instead of the median. So if you want to cut out the nonsense, take the median and not the average.