For the "Last Ball in Play" sockets, those have a 35ohm resistor instead of the 75ohm, and a 455 flasher bulb has to be used.
#44s are .25 amp and #47s are .15 amp. 47s will certainly light for awhile (and brightly!), but will burn out after a short time. The #44s are fine there (since that's what the sand resistor was sized for). It's not been my observation that the #44s are brighter/hotter/shorter life in that application. #47s most definitely will in those sockets.
A quick math check would be 25V-6.3V = 18.7V; 18.7V/0.25A = 74.8ohms (so there's the 75 ohms). (I used 25V instead of 24V, after checking a 1960's schematic; it's 25V on the schematic.)
If one wanted to use #47s instead, then would need 18.7V/0.15A = 124.7ohms, or call it 125ohm resistor. Could do that by replacing all those resistors.
Otherwise you're running 25V-(0.15A)*(75ohms) = 25V-11.25V = 13.75V through a 6.3V bulb using #47s. Yes, they're very bright (and short-lived).
455s are 6.5V and 0.5A, so 25V-6.5V = 18.5V/0.5A = 37ohms. They use 35ohm resistors on those (there's probably another couple ohms in series with it via a relay in the circuit).
The net is, use #44s with the 75ohm resistors, and #455 flashers with the 35ohm resistors. Or plan on changing resistors to match the load.