Quoted from Rockytop:
If you asked me to pick the best 2 out of that group 10 times I might give 10 different answers. (If that’s mathematically possible, it’s late and I’m not doing math)
Not mathematically possible...
you have only 6 ways of choosing 2 pins in a list of 4: n= 4! / ((4-2)!x2!))
If the four pins are A, B, C, D, the 6 possibilities are: