Quoted from metallik:But the difference is the wrong way. 800 turns will have higher resistance and less power than 600 turns of the same gauge wire.
Stop focusing on a single number and read the equation that determines force in a solenoid.
https://www.daycounter.com/Calculators/Magnets/Solenoid-Force-Calculator.phtml
F = (N*I)**2 μ0 A / (2 g**2),
Where:
μ0 = 4π10-7
F is the force in Newtons
N is the number of turns
I is the current in Amps
A is the area in length units squared
g is the length of the gap between the solenoid and a piece of metal.
Note, any units can be used for A and g so long as they are consistent. For example, in2 and in, or m2 and m, respectively.
As we are assuming the geometry to be the same we can drop it and the constant μ0 from the discussion. That basically leaves the effects of the # of turns and the current. The # of turns effects the Force as a square, as does the current. As they are multiplied before the square they are basically in a proportional relationship in the equation. So which has the bigger effect on the square when one changes?
The current is a function of resistance (inversely proportional), and resistance a function of gauge and length. The resistance per foot of 23awg is roughly .02036 ohms.
American Wire Gages (AWG) Sizes and Resistances
https://www.google.com/search?client=firefox-b-1-d&q=resistance+per+foot+23+awg
AWG wire size (solid) Area CM* Resistance per 1000 ft (ohms) @ 20 C
22 642.4 16.14
23 509.45 20.36
24 404.01 25.67
25 320.4 32.37
How many foot do you need for 200 turns on a flipper coil, and then multiply that by .020 ohms. I'm betting that we don't need many feet. So the extra resistance is small and therefore the current falls by a small %. I.e. The effect of resistance on the current for 200 turns is much lower so the current number will go down only slightly.
However, the turns number went up by 33% (800 vs 600, or 200 more turns). Thus the # of turns will have a much greater effect on the total force that the coil can exert on the plunger.