Quoted from AFM95:
Winning percentage is calculated by all matchups, not who is left. For example, JJP has had pins in 10 matchups. Their record for their 10 matchups is 6 wins, 4 losses. Winning percentage is calculated by wins/# of total matchups.
Standings in most major sports use winning percentages to determine standings. We all know Stern would win if we just counted wins, but winning percentage evens the playing field a bit. It's not perfect - i.e. If The Big Lewbowski won its first two matchups, then lost, Dutch Pinball would have a .667 winning percentage and would be crowned the best manufacturer in the tournament. However, with one game and a little luck, the optics are obviously saying we need a bigger sample size. Same goes for Spooky. They had their two games lose right away. What if they won their first round matchups? They would have at minimum a .500 record.
So again, not a perfect science, but it's a good way to measure Stern versus Williams, or Bally's versus JJP, etc. when opportunities aren't equal for all manufacturers.
Sorry for the long explanation, but I hope that helps.
Helpful, but doesn't account for a " Bally eating a Bally, Stern eating Stern, etc."
Like NFC vs. AFC , East vs West, etc. in sports.
When NFC beats NFC, it doesn't count in conference W/L.
I think if you looked at each manufacturer beating or losing to another, that would easily give an accurate view of which companies truly had the highest winning %.
No biggie, and just really appreciate you doing this...something fun