(Topic ID: 150318)

Quick Resistor Question

By deershoot3r

8 years ago


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    #1 8 years ago

    Im wiring some LEDs in parallel, 8 to be exact. Im using 12v as the power source and the LEDs need 3.3 volts of power and only use 20mA a piece. Im using a resistor calculator online, just because its a lot faster than I am. The resistor calc says i need a 2 watt resistor, but that doesnt seem right because the LEDs arent putting out but .528 Watts. Did i do my math wrong? Could someone tell me what i should be using or explain why its 2 watts instead of a 1/2 watt or 1 watt resistor?

    Any Help is greatly appreciated!

    Thanks,
    deershoot3r

    #2 8 years ago

    I calculated your problem to be only needing 1/8 W resistors. Not sure why you are coming up with 2 watt resistors. Two of the resistors dissipate 37mW, and one dissipates 88mW using this calculator: http://ledcalc.com/

    #3 8 years ago

    I got the same answer too, using "the guru" calculator, but im trying to use parallel instead because of a single resistor not multiple.

    #4 8 years ago

    I'm getting 1392mW at ~56Ω but not sure i'm doing it correct.

    ohm_(resized).PNGohm_(resized).PNG

    #5 8 years ago
    Quoted from zaza:

    I'm getting 1392mW at ~56Ω but not sure i'm doing it correct.

    That is correct, and then a *safe* resistor wattage to use for 1.3W would be 2.5W

    Have you thought about using an LED driver device instead of a big resistor?

    #6 8 years ago

    You are better off using one lower power resistor per LED rather than one higher powered one for reasons detailed in this thread:

    http://electronics.stackexchange.com/questions/22291/why-exactly-cant-a-single-resistor-be-used-for-many-parallel-leds

    So in your case

    RLED = (12-3.3)/.020 = 435 nearest preferred value is 432R 1% or 430R 5%

    Power dissipated in each resistor
    P = I^2R = .173W so use a 432R resistor rated at 1/4W or more

    #7 8 years ago

    @woz okay i like that, thats how i wired another project up so im just gonna use that method, thanks everyone for their help!!

    #8 8 years ago

    Alright ive added up the value of a different LED, make sure i have this right, this LED only needs 2.3 volts of power instead of 3.3, Voltage stays at 12, and amps stay at 0.020
    so if
    R=(12-2.3)/0.020= 485
    and P = I^2R = 0.194

    Then i should i User a higher resistor like a 487ohm 1/4 watt 1% tolerence or should i try to stay lower than the resistance above?

    #9 8 years ago

    Stay with the higher.

    #10 8 years ago

    Thank you sir! (or maam)

    #11 8 years ago

    If you put three LEDs in series you won't have to burn off as much voltage in the resistors.

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