(Topic ID: 313762)

Opto foked Williams pinball mount question

By csab00

2 years ago



Topic Stats

  • 7 posts
  • 4 Pinsiders participating
  • Latest reply 2 years ago by pins4u
  • No one calls this topic a favorite

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    #1 2 years ago

    Hi!

    I wanted to solder an old S-1865 to a Whirlwind small opto board.
    Unfortunately i cannot decide what side is the transistor and the diode.
    On the part i have found one marked leg. (see the picture)
    What has been marked on this leg ?

    Thanks in advance!

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    #2 2 years ago

    Most have some markings on top like pic below. The + above the E is pin one.

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    #3 2 years ago

    There is nothing on the top of the part...

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    #4 2 years ago

    What you think is pin #1 on your opto, lines up with my opto's pin #1. So that is what I would try.

    #5 2 years ago

    Try this:

    1. Get out your DMM.
    2. Set it to diode test.
    3. Test red lead to black lead of each of the legs.
    4. The legs that register a voltage drop are the anode (A=red lead) and cathode (K=black lead).

    I just tried this on a different slotted opto pair and there is every reason it should apply to your slotted opto pair.

    #6 2 years ago
    Quoted from DumbAss:

    Try this:

    Get out your DMM.
    Set it to diode test.
    Test red lead to black lead of each of the legs.
    The legs that register a voltage drop are the anode (A=red lead) and cathode (K=black lead).

    I just tried this on a different slotted opto pair and there is every reason it should apply to your slotted opto pair.

    Hi!

    Yes that was a good idea!
    1. leg pair : 1.019
    2. leg pair : 1.355 (but this side is always alternating, the measure is not precise it was 1.5 and 1.7)

    I am not familiar with optos may the receiver (diode) get some electricty from the dmm thats why the different values no idea ...

    #7 2 years ago

    The receiver side is a transistor without a base leg. Only Collector and Emitter.

    That's why the IR Transmitter DIODE can easily be determined but the resistance between collector and emitter is not easily measured like you are finding - it will fluctuate.

    pasted_imagedata2 (resized).pngpasted_imagedata2 (resized).png

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