(Topic ID: 155307)

Increasing the power to a coil, remove more windings?

By jodini

8 years ago


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Topic Stats

  • 16 posts
  • 11 Pinsiders participating
  • Latest reply 3 years ago by MarkG
  • Topic is favorited by 2 Pinsiders

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    #3 8 years ago

    More current = more magnetic pull

    Ohm's Law ... I = V/R where,
    ...I = Current
    ...V = Voltage
    ...R = Resistance

    Holding voltage constant, reducing resistance (with fewer windings), increases current.
    There are tradeoffs.

    I'm sure a bonafide EE can chime in.
    --
    Chris Hibler - CARGPB #31
    http://ChrisHiblerPinball.com/contact/
    http://webpages.charter.net/chibler/Pinball/index.htm
    http://www.PinWiki.com - The Place to go for Pinball Repair Info

    #9 8 years ago

    The easiest demonstration would be to power two WMS coils side by side, powered from the same source, and devise a method to test magnetic pull. Perhaps ability to hold a paper clip attached to a string in mid air. The -1200 will be able to hold it at a longer distance.

    The 26-1500 and 26-1200 would work well since both use the same gauge wire and the same size bobbin.
    --
    Chris Hibler - CARGPB #31
    http://ChrisHiblerPinball.com/contact/
    http://webpages.charter.net/chibler/Pinball/index.htm
    http://www.PinWiki.com - The Place to go for Pinball Repair Info

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