(Topic ID: 232727)

Help with Capacitor to Replace Battery on Gottlieb 80b


By ezatnova

5 months ago



Topic Stats

  • 8 posts
  • 3 Pinsiders participating
  • Latest reply 5 months ago by ezatnova
  • Topic is favorited by 2 Pinsiders

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    3F6D6901-2612-4461-B393-AE3097A801D5 (resized).jpeg
    Gottlieb_R7a (resized).jpg
    Gottlieb_battery (resized).jpg
    D51E27EF-1D38-4C2D-B89E-68F18A254B86 (resized).jpeg
    B6122B67-D0F0-4738-B889-691CA3A21523 (resized).jpeg

    #1 5 months ago

    Hello,

    Watched the tutorials posted in this forum and thought that since my battery was replaced 3 years ago, I should go ahead and replace that one with a final fix of the capacitor on my Raven.

    Got what I am very sure is the correct capacitor (5.5v 1.5f). Figured it would save a ton of desoldering and board removal hassle if I just snipped the battery off the board, leaving the little metal leads from the battery soldered as they were. I then soldered some wires to the capacitor and put some female pin connectors on the other ends of the wires from the capacitor. These slipped perfectly over those remaining old battery leads, soldered into the board.

    I Put the negative wire to the unmarked lead and the positive to the one with the little + near it on the board. I let the game sit plugged in for a bit to make sure the capacitor charged. After turning the game on, the first bad sign was that all high scores and credits were gone.

    Added some credits and turned the machine off. Turned it back on after 5 minutes and it shows 0 credits again.

    I’m at a real loss. This seems like a pretty darn simple procedure! For what it’s worth, with the game powered on, and the capacitor unplugged from the board (so there is just the two bare old leads from the removed battery), I get 0 volts across the old leads soldered into the board. Shouldn’t I see voltage? How else would it charge the capacitor?

    Any other thoughts or trouble shooting tips are welcome!!
    B6122B67-D0F0-4738-B889-691CA3A21523 (resized).jpegD51E27EF-1D38-4C2D-B89E-68F18A254B86 (resized).jpeg

    #2 5 months ago

    Is the original battery a rechargeable one? If it isn't, there's going to be a blocking diode in the circuit to prevent a non-recharageable from being charged that will need to be jumped out or replaced with a wire jumper.

    You tell by measuring the + terminal with a meter when the game is on - no voltage=diode blocked. The schematics don't really call out that section it just says "B+" on the 5101 input.

    #3 5 months ago
    Quoted from slochar:

    Is the original battery a rechargeable one?

    It is.
    Without blocking diode will work perfectly.
    I had a Counterforce once with a cap on it and it held the memory for a year in storage.

    #4 5 months ago

    If I look at this clossely, I see you replaced R7 with a 2N4001 diode.
    Why did you do this?
    Now you do not get any voltage to the cap, thus it will not charge.
    Just put the R7 back in and you will be fine.

    Gottlieb_battery (resized).jpg
    #5 5 months ago
    Quoted from Inkochnito:

    If I look at this clossely, I see you replaced R7 with a 2N4001 diode.
    Why did you do this?
    Now you do not get any voltage to the cap, thus it will not charge.
    Just put the R7 back in and you will be fine.
    [quoted image]

    I have no idea. Had my machine repaired a few years ago and the repairman put this board in it with the little 3.6v battery soldered in there. He must have had it all set up to work correctly with the non rechargeable battery. I’m a novice at this so can you clarify what an R7 is and where it should go please?

    #6 5 months ago

    The black thing at the end of the white arrow is a diode 2N4001.
    This needs to be replaced by a resistor of 50 to 100 ohm to charge the capacitor.
    Otherwise it will not work.

    Gottlieb_R7a (resized).jpg
    #7 5 months ago
    Quoted from Inkochnito:

    The black thing at the end of the white arrow is a diode 2N4001.
    This needs to be replaced by a resistor of 50 to 100 ohm to charge the capacitor.
    Otherwise it will not work.
    [quoted image]

    Ah. Thanks!

    Attaching a pic of the whole board here in case there is anything else that looks odd that I need to know about.

    3F6D6901-2612-4461-B393-AE3097A801D5 (resized).jpeg
    1 week later
    #8 5 months ago

    Thanks Inkochnito, it worked as soon as I replaced that diode with a resistor!

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