Hi!

I was replacing some of my ramp switches and got new ones and new diodes and soldered it all back together like it was before so i think i have done it right.

Here is what i did, example:

The switch has 3 legs, that are from the left Normally closed, middle normally open and to the right the common.
White/vio wire goes on the NC pin and the grn/blu to the mid pin. The diode 1N4004 goes from C to NC and has the banded side towards C. So far so good.

I thought it would be a good idea to test the functionality before putting them back on the ramps where they reside. So i took my DMM and buzzed the switch. Now i thought that ok, when the switch is pressed there should be continuity between the two wires i soldered there but no.

What happens is when measured from:

C to NO - buzz heard WHEN switch is closed
C to NC - buzz heard UNTIL switch is closed
NO to NC - nothing at all

This is probably correct but it lead me to get confused... I just cant figure out why the wires just dont go from common to NO and when the switch is pressed the circuit is closed. I guess the diode has something to do with this since it goes from NC to C. I understand it should prevent the switch from "backfiring" into the switch matrix but not exactly how more than it keeps the current flowing in the right direction as opposed to backfiring in the solenoid context. I just neeeed to know!!

Below is a sketch i made of how the switch functions but as i said i cant figure out the diode... anyone who can explain it?

switch.png

/Andy

btw75, so that would mean that the current flows from the wire at NC, through the diode and (if the switch is closed) through the NO wire and back through the matrix.

If its open, it just goes to NC but not any further since it only would loop back and also the diode is blocking it at the C-lug...

Patofnaud, i will read up on it again, ive tried a couple of times but I only understand part of it each time

Thanks! I will have a look at it =)