Let's do the lower left, first. ( Please study what I am saying below. It is not easy to describe wiring. Sorry. ). Get to know this lower LEFT flipper circuit cold. And then know that the lower RIGHT hand circuit is exactly the same except the the green wire has been replaced with an orange wire that travels to connector J-1 on the SDU board.
Once you have the two lower flippers figure out, realize that the two upper flippers are wired just the same except for resistors. Once you have understanding of the lower flippers, then we can work the resistors on the uppers.
If you have any questions, then ask them. Don't be shy.
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Is the lower left flipper working? If not, then let's fix it.
Before I get started, the lower left flipper has 2 switches; 1 switch is the EOS switch that opens when you press the flipper button. The other switch is the power supply to the upper flipper; This switch closes when you press the flipper button. Keep this in your thought processor.
From your pic:
1 A) The blue white wire is correct. It comes from the hot side of the fuse holder and lives above the diode band on the coil lugs.
There is a 2nd blue/white wire at the fuse holder. It will feed power to the other 3 flippers; Each of those other 3 flippers should have two Blu/W wires soldered to the lug above the diode band to complete the Blu/W flipper wire daisy chain.
1 B) Along with the Blu/W wire, there is also one black wire that leads to the EOS switch (This black wire would be better if it was a Blu/W jumper wire.). On the center lug is another black wire that leads to a different lug on the EOS switch---this completes the circuit on the EOS switch. The EOS switch contains one Blu/W wire above the diode band; one black (again, better if this wire was Blu-W) wire above the diode band; and one black wire (center lug) that installs below the diode band.
2) This next explanation is a little tricky as yours is wired different than mine. The third lug on the coil is below the diode band. This is the green wire that comes from connector J-1 on the SDU board. This is the wire that completes left hand flipper circuit This lug also has a black jumper wire wire that leads to the the non-EOS switch of the switch pair (If you look carefully, you will see that my black wire has broken and is sitting next to a 2nd green wire. This 2nd green wire, leading from the closing switch, travels up to the left upper flipper switch and also completes the lower left flipper circuit.
NOTE: Instead of a black wire being paired with a green wire at the coil lug, it could (and should be, IMO) be a green wire that leads from the coil lug to the closing switch.
I'll try to condense the above to make it easier to understand.
A) Blu/W power wire feeds the coil lug above the diode band. It also feeds power to the EOS switch. The other side of the EOS switch is a black wire that travels back to the center coil lug, which is below the diode band.
B) The green wire that completes the flipper circuit attaches to the coil lug below the diode band. The black ( should be green ) wire travels from the coil lug down to the closing switch. The other side of the closing switch has a green wire that travels to the UPPER left flipper.
Here is the blueprint for the left lower and upper flipper coils ( I also just noticed that the EOS switch is drawn incorrectly. The EOS switch is associated with the the B/W wire, not the green wire as presented in this drawing. ( It is not the first instance of Stern screwing up the drawings).
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Here it is corrected.
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You can click on this pic to make it larger.
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